{"id":126,"date":"2014-11-10T08:23:10","date_gmt":"2014-11-10T08:23:10","guid":{"rendered":"http:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/ppp-exercise-4b\/"},"modified":"2014-11-17T08:09:54","modified_gmt":"2014-11-17T08:09:54","slug":"ppp-exercise-4b","status":"publish","type":"page","link":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/ppp-exercise-4b\/","title":{"rendered":"PPP Exercise 4B"},"content":{"rendered":"<p>1. A circuit consists of two resistors connected in series.<\/p>\n<p style=\"text-align: center\"><a href=\"https:\/\/blogs.glowscotland.org.uk\/gc\/public\/hyndsecphyprelimpractice\/uploads\/sites\/5115\/2014\/11\/Picture2.png\"><img decoding=\"async\" class=\"aligncenter size-full wp-image-150\" title=\"Picture2\" src=\"https:\/\/blogs.glowscotland.org.uk\/gc\/public\/hyndsecphyprelimpractice\/uploads\/sites\/5115\/2014\/11\/Picture2.png\" alt=\"\" width=\"460\" height=\"244\" srcset=\"https:\/\/blogs.glowscotland.org.uk\/gc\/public\/hyndsecphyprelimpractice\/uploads\/sites\/5115\/2014\/11\/Picture2.png 767w, https:\/\/glow-prod-gc.s3.eu-west-1.amazonaws.com\/gc\/public\/hyndsecphyprelimpractice\/uploads\/sites\/5115\/2014\/11\/Picture2-300x159.png?X-Amz-Content-Sha256=UNSIGNED-PAYLOAD&amp;X-Amz-Security-Token=IQoJb3JpZ2luX2VjEGgaCWV1LXdlc3QtMSJHMEUCIQD2B4H6wYIvKsBqDHpUupMQAz6LjpoRxE8UOZ6FVByr6wIgBGZyA5jYzJDQ6iUwdHXKEDEynvdnHVfmD7qrcfrUtmEquAUIMRAFGgwyNzM1NzAxOTU0MzMiDNf3VlH90fgrab0wOCqVBdA50wX40JnBo3%2FiqkVNN3nH07VsyH0uVp3N2F40NgZ%2B55B9r34OW2W4KlpWpgIIJusUEo%2FIqtXbt%2FbyMpT%2BXvbHaE0qrnszo2ZxXMjxiYgnACIGL90XhkmFDVS4PHvjNDlwsW3%2B1qKw9FSet7px08eWEtjtDzFkRJCULqigCR6UAg6Rg0atEtcJNAdy%2BWP1cGvfGy3y9Ch9Yy%2FBVDk2G%2FDUJVDA88jN6BVMYpne%2F9WvK8RuJHr9i6PqGSWCi1kTf%2BeLKE5sjBC9JULmBC%2FbOuuDe3i%2BSWp1ek7HARo3XAwEru2H4SlntxBmQw57sXbTfvDYk1GZOrktlLDb4LMTTi6ur3cTCSAOZg0xl2I%2B4Iliy9xiSsqlTiw8hPwkllpLQntwanWSOZq86NrU0rdTH4tGK0rNJoMM2gdgLi2aQTU7iHzisEMoK49XiHWLwN14YflSzhT3QTKj3c5f805P2TFlf6GEdATp228gI0nsAJ3knfIVOiX0G09Ap4hJTR2ozcQPbXLj7iZY4sabjKVbqG7DMVof1HqVchysdUVHBs%2BV9uXvGLrUhU3Qlu2sspIIngiQi9RlIwjzeR3cP7Pd0%2FtHzefRKDCJ4qHJ5x8e9BBUL7FBijR1yD3Tz3G1vYqlA1kKQ3c1239GJnD%2FKGBk4novkqU3aO8sMsgZDOYkBII63Pboojyiuhoese7Dro0b440sCnuhSnB1yQ2kIualmKoSnjvv5f9fB4ItGlhXXJB0dk3qpuXRQJkdazsUMAte6i9Fij3w4OdhcyWIRQ%2FUayVVwxnDI714NUHw8BMT2SmuFb%2FpXy5g8djv4yBJkEEtMgFU3mXKMEi%2Fcn1t0E4ZKDyT62aBcME7Mdw9mjdwU3SXpsJI8aQwsdyg1gY6sQHClYTs8GcxRQSbPP2UCdnWV37tujLgAoh8cxpAjHtT9QnkjRjc7iNUUAMcVjVrVdmYYjoEdLS1PKwlOO9PbCmSeHe%2F1eHmWFBtNOIFR%2FYBOmZ13cBCCvx3DG4G2G9n7wSmiM4Ncq8FFmnfXhH9p4P6gTzDqGRlHY%2BDz70GpRiiaIh5iZJ6n%2BK97azEGZpc8TYWAl2DGetq7ZWBmJzOkY%2BDdYGTaUFx3VjijmdDFuCl9ro%3D&amp;X-Amz-Algorithm=AWS4-HMAC-SHA256&amp;X-Amz-Credential=ASIAT7MQN47UY2OFWSKO%2F20261009%2Feu-west-1%2Fs3%2Faws4_request&amp;X-Amz-Date=20261009T002823Z&amp;X-Amz-SignedHeaders=host&amp;X-Amz-Expires=900&amp;X-Amz-Signature=d10884042c278b3ace01b23fd5fab1dde0d4c3dfc5b60a436f49777662176993 300w\" sizes=\"(max-width: 460px) 100vw, 460px\" \/><\/a><\/p>\n<p>(a) Calculate the total resistance of the circuit.<br \/>\n(b) A 9 V cell is used as the power source. Calculate the current in the circuit<br \/>\n(c) Calculate the readings on:<br \/>\n(i) Voltmeter V1;<br \/>\n(ii) Voltmeter V2.<br \/>\n2. A pupil connects three resistors as shown in the circuit below.<\/p>\n<p><a href=\"https:\/\/blogs.glowscotland.org.uk\/gc\/public\/hyndsecphyprelimpractice\/uploads\/sites\/5115\/2014\/11\/Picture3.png\"><img decoding=\"async\" class=\"aligncenter size-full wp-image-151\" title=\"Picture3\" src=\"https:\/\/blogs.glowscotland.org.uk\/gc\/public\/hyndsecphyprelimpractice\/uploads\/sites\/5115\/2014\/11\/Picture3.png\" alt=\"\" width=\"353\" height=\"398\" srcset=\"https:\/\/blogs.glowscotland.org.uk\/gc\/public\/hyndsecphyprelimpractice\/uploads\/sites\/5115\/2014\/11\/Picture3.png 353w, https:\/\/glow-prod-gc.s3.eu-west-1.amazonaws.com\/gc\/public\/hyndsecphyprelimpractice\/uploads\/sites\/5115\/2014\/11\/Picture3-266x300.png?X-Amz-Content-Sha256=UNSIGNED-PAYLOAD&amp;X-Amz-Security-Token=IQoJb3JpZ2luX2VjEGgaCWV1LXdlc3QtMSJHMEUCIQD2B4H6wYIvKsBqDHpUupMQAz6LjpoRxE8UOZ6FVByr6wIgBGZyA5jYzJDQ6iUwdHXKEDEynvdnHVfmD7qrcfrUtmEquAUIMRAFGgwyNzM1NzAxOTU0MzMiDNf3VlH90fgrab0wOCqVBdA50wX40JnBo3%2FiqkVNN3nH07VsyH0uVp3N2F40NgZ%2B55B9r34OW2W4KlpWpgIIJusUEo%2FIqtXbt%2FbyMpT%2BXvbHaE0qrnszo2ZxXMjxiYgnACIGL90XhkmFDVS4PHvjNDlwsW3%2B1qKw9FSet7px08eWEtjtDzFkRJCULqigCR6UAg6Rg0atEtcJNAdy%2BWP1cGvfGy3y9Ch9Yy%2FBVDk2G%2FDUJVDA88jN6BVMYpne%2F9WvK8RuJHr9i6PqGSWCi1kTf%2BeLKE5sjBC9JULmBC%2FbOuuDe3i%2BSWp1ek7HARo3XAwEru2H4SlntxBmQw57sXbTfvDYk1GZOrktlLDb4LMTTi6ur3cTCSAOZg0xl2I%2B4Iliy9xiSsqlTiw8hPwkllpLQntwanWSOZq86NrU0rdTH4tGK0rNJoMM2gdgLi2aQTU7iHzisEMoK49XiHWLwN14YflSzhT3QTKj3c5f805P2TFlf6GEdATp228gI0nsAJ3knfIVOiX0G09Ap4hJTR2ozcQPbXLj7iZY4sabjKVbqG7DMVof1HqVchysdUVHBs%2BV9uXvGLrUhU3Qlu2sspIIngiQi9RlIwjzeR3cP7Pd0%2FtHzefRKDCJ4qHJ5x8e9BBUL7FBijR1yD3Tz3G1vYqlA1kKQ3c1239GJnD%2FKGBk4novkqU3aO8sMsgZDOYkBII63Pboojyiuhoese7Dro0b440sCnuhSnB1yQ2kIualmKoSnjvv5f9fB4ItGlhXXJB0dk3qpuXRQJkdazsUMAte6i9Fij3w4OdhcyWIRQ%2FUayVVwxnDI714NUHw8BMT2SmuFb%2FpXy5g8djv4yBJkEEtMgFU3mXKMEi%2Fcn1t0E4ZKDyT62aBcME7Mdw9mjdwU3SXpsJI8aQwsdyg1gY6sQHClYTs8GcxRQSbPP2UCdnWV37tujLgAoh8cxpAjHtT9QnkjRjc7iNUUAMcVjVrVdmYYjoEdLS1PKwlOO9PbCmSeHe%2F1eHmWFBtNOIFR%2FYBOmZ13cBCCvx3DG4G2G9n7wSmiM4Ncq8FFmnfXhH9p4P6gTzDqGRlHY%2BDz70GpRiiaIh5iZJ6n%2BK97azEGZpc8TYWAl2DGetq7ZWBmJzOkY%2BDdYGTaUFx3VjijmdDFuCl9ro%3D&amp;X-Amz-Algorithm=AWS4-HMAC-SHA256&amp;X-Amz-Credential=ASIAT7MQN47UY2OFWSKO%2F20261009%2Feu-west-1%2Fs3%2Faws4_request&amp;X-Amz-Date=20261009T002823Z&amp;X-Amz-SignedHeaders=host&amp;X-Amz-Expires=900&amp;X-Amz-Signature=deb35377bf8d8ed866a06d6f05a194b44cb22fa16cbeff4bdfd4050808aa7e19 266w\" sizes=\"(max-width: 353px) 100vw, 353px\" \/><\/a><\/p>\n<p>(a) Calculate the total resistance of the circuit.<br \/>\n(b) The current through the 4 \uf057 resistor is 3 A. Calculate the voltage across R3.<br \/>\n(c) State the voltage across R1 and R2.<br \/>\n(d) State the reading on meter V1.<br \/>\n(e) Calculate the current through:<br \/>\n(i) Resistor R1;<br \/>\n(ii) Resistor R2.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>1. A circuit consists of two resistors connected in series. (a) Calculate the total resistance of the circuit. (b) A 9 V cell is used as the power source. Calculate the current in the circuit (c) Calculate the readings on: (i) Voltmeter V1; (ii) Voltmeter V2. 2. A pupil connects three resistors as shown in &hellip; <a href=\"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/ppp-exercise-4b\/\" class=\"more-link\">Continue reading <span class=\"screen-reader-text\">PPP Exercise 4B<\/span> <span class=\"meta-nav\">&rarr;<\/span><\/a><\/p>\n","protected":false},"author":2454,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"open","ping_status":"open","template":"","meta":{"footnotes":""},"class_list":["post-126","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/wp-json\/wp\/v2\/pages\/126","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/wp-json\/wp\/v2\/users\/2454"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/wp-json\/wp\/v2\/comments?post=126"}],"version-history":[{"count":3,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/wp-json\/wp\/v2\/pages\/126\/revisions"}],"predecessor-version":[{"id":153,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/wp-json\/wp\/v2\/pages\/126\/revisions\/153"}],"wp:attachment":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/wp-json\/wp\/v2\/media?parent=126"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}