{"id":126,"date":"2014-11-10T08:23:10","date_gmt":"2014-11-10T08:23:10","guid":{"rendered":"http:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/ppp-exercise-4b\/"},"modified":"2014-11-17T08:09:54","modified_gmt":"2014-11-17T08:09:54","slug":"ppp-exercise-4b","status":"publish","type":"page","link":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/ppp-exercise-4b\/","title":{"rendered":"PPP Exercise 4B"},"content":{"rendered":"<p>1. A circuit consists of two resistors connected in series.<\/p>\n<p style=\"text-align: center\"><a href=\"https:\/\/blogs.glowscotland.org.uk\/gc\/public\/hyndsecphyprelimpractice\/uploads\/sites\/5115\/2014\/11\/Picture2.png\"><img decoding=\"async\" class=\"aligncenter size-full wp-image-150\" title=\"Picture2\" src=\"https:\/\/blogs.glowscotland.org.uk\/gc\/public\/hyndsecphyprelimpractice\/uploads\/sites\/5115\/2014\/11\/Picture2.png\" alt=\"\" width=\"460\" height=\"244\" srcset=\"https:\/\/blogs.glowscotland.org.uk\/gc\/public\/hyndsecphyprelimpractice\/uploads\/sites\/5115\/2014\/11\/Picture2.png 767w, https:\/\/glow-prod-gc.s3.eu-west-1.amazonaws.com\/gc\/public\/hyndsecphyprelimpractice\/uploads\/sites\/5115\/2014\/11\/Picture2-300x159.png?X-Amz-Content-Sha256=UNSIGNED-PAYLOAD&amp;X-Amz-Security-Token=IQoJb3JpZ2luX2VjEFAaCWV1LXdlc3QtMSJGMEQCICGQQGH1IPhgV6LVxYYeJfuvEV7JRPGZSeIw3F9W%2F8EFAiAM4PzdvnuO1C3C1P2nlRVeGIVverCJWWRX1KrSiH3GXSq5BQgZEAUaDDI3MzU3MDE5NTQzMyIM0RIj0F0vMvOCMTHgKpYFE4%2F5IuTEq9vI8rot%2BlyI2NB8e5%2By3nhhdK7%2BpMWAgUiOqnDxT6tVEK6N%2Bm8WiLbB%2B30bbIJ5BIIWCY7sp3FkrGPlBDKuHQ5UiP2azCUtsBwUPp5uAFvu08l4HULUDXq8ssewEr1eK6US6GixQcoSlFkIJpC7e8n1cP1X8n%2FdOYKpq1cZhIffadiJ9az5RCGzCtIjI%2FeWDMARcYkGepkaLKo0lo%2ByC9PKaW7AqJHuXUNJ5iKt40wJ2iP5pQSQYwm9zGljdrKHnhEah%2B6uVrwEvflcnsaUNLIi9nQKje7cx6tK5l5u1f5e5nbzEXDCnq4F7Yod4LcHdxDi0zJvKa97Hu8SFupBi%2F07a59yRE1QPoJP4Ad%2Big%2FwEGaG1Q0O%2FCGUjqY6Xii1Hm6q6XBx0ArQ4gg%2BTqzssFD6gdX%2FD1PQZdMrR5euP8C3eYDfV%2B%2FRRjWVpuA3ETduebMgxjXsqU896hpNcwm7OcsVIqrxCw4OGC0Q9gn8eywogLmNnmaZGleLyv048q4ZSJr%2FHV9GuT5TxivcDg2GVV%2BZWgJ7gG7Jc3xOS4T5fDb9ey3OSyySxK4hGK4oXvHsl7VlNogBdoCeULNDCO6iOWVq10WkhjCsgozJSzb1LOu3zUHSzPV28aLQTUHaEnqdG67u%2Faf0IyN337tD5qQ4uJdDkNunpgHVhsspAM5%2BSx849%2BJR7XprkXuEs%2BkUmXzTHG9ST%2BugywMDZo0C41q%2FWK2w4RUcI%2F%2Bt7vZQiHyIUGLQILD5eIqf8HEwz63LZOVgDFiSRG7cGc1goTGX%2FFb%2FYf2hAtsflPYOKMBiYy1CwNJ57rVKo8JqNTmTUufhCD05Dqf7RPE5q4nerFvi1SLg4TrXFUtw37HwggIzJJKaLIgww%2BuL1wY6sgFC%2F8kuSwxNekGBFnPrHu%2FTGf%2BD%2FBz6u6pRTe%2Fb67YKxcLm2Dymt%2Fiy2VmZ6RdX8V98hPLeA1sWQjb6ppd20Q4JoYF3%2FWQ0bsouk7SXjkRs8Fk21WDePnYv2oBC8P3mCo9tDuLyUv8MbxuamlcenIb9nmRojb%2Bh8hZ58oKR4XxjQTcYcjClN7WICACxZCEEgiLvk25iO6CeBDWXfhRlR6inT3QdNV4tYFMesY0Rb1YymoRr&amp;X-Amz-Algorithm=AWS4-HMAC-SHA256&amp;X-Amz-Credential=ASIAT7MQN47UX2GMWDFB%2F20261029%2Feu-west-1%2Fs3%2Faws4_request&amp;X-Amz-Date=20261029T080859Z&amp;X-Amz-SignedHeaders=host&amp;X-Amz-Expires=900&amp;X-Amz-Signature=26e9bb37d497bbf784f2952097603d6c293915f26312058e06f8427fd8d58ca1 300w\" sizes=\"(max-width: 460px) 100vw, 460px\" \/><\/a><\/p>\n<p>(a) Calculate the total resistance of the circuit.<br \/>\n(b) A 9 V cell is used as the power source. Calculate the current in the circuit<br \/>\n(c) Calculate the readings on:<br \/>\n(i) Voltmeter V1;<br \/>\n(ii) Voltmeter V2.<br \/>\n2. A pupil connects three resistors as shown in the circuit below.<\/p>\n<p><a href=\"https:\/\/blogs.glowscotland.org.uk\/gc\/public\/hyndsecphyprelimpractice\/uploads\/sites\/5115\/2014\/11\/Picture3.png\"><img decoding=\"async\" class=\"aligncenter size-full wp-image-151\" title=\"Picture3\" src=\"https:\/\/blogs.glowscotland.org.uk\/gc\/public\/hyndsecphyprelimpractice\/uploads\/sites\/5115\/2014\/11\/Picture3.png\" alt=\"\" width=\"353\" height=\"398\" srcset=\"https:\/\/blogs.glowscotland.org.uk\/gc\/public\/hyndsecphyprelimpractice\/uploads\/sites\/5115\/2014\/11\/Picture3.png 353w, https:\/\/glow-prod-gc.s3.eu-west-1.amazonaws.com\/gc\/public\/hyndsecphyprelimpractice\/uploads\/sites\/5115\/2014\/11\/Picture3-266x300.png?X-Amz-Content-Sha256=UNSIGNED-PAYLOAD&amp;X-Amz-Security-Token=IQoJb3JpZ2luX2VjEFAaCWV1LXdlc3QtMSJGMEQCICGQQGH1IPhgV6LVxYYeJfuvEV7JRPGZSeIw3F9W%2F8EFAiAM4PzdvnuO1C3C1P2nlRVeGIVverCJWWRX1KrSiH3GXSq5BQgZEAUaDDI3MzU3MDE5NTQzMyIM0RIj0F0vMvOCMTHgKpYFE4%2F5IuTEq9vI8rot%2BlyI2NB8e5%2By3nhhdK7%2BpMWAgUiOqnDxT6tVEK6N%2Bm8WiLbB%2B30bbIJ5BIIWCY7sp3FkrGPlBDKuHQ5UiP2azCUtsBwUPp5uAFvu08l4HULUDXq8ssewEr1eK6US6GixQcoSlFkIJpC7e8n1cP1X8n%2FdOYKpq1cZhIffadiJ9az5RCGzCtIjI%2FeWDMARcYkGepkaLKo0lo%2ByC9PKaW7AqJHuXUNJ5iKt40wJ2iP5pQSQYwm9zGljdrKHnhEah%2B6uVrwEvflcnsaUNLIi9nQKje7cx6tK5l5u1f5e5nbzEXDCnq4F7Yod4LcHdxDi0zJvKa97Hu8SFupBi%2F07a59yRE1QPoJP4Ad%2Big%2FwEGaG1Q0O%2FCGUjqY6Xii1Hm6q6XBx0ArQ4gg%2BTqzssFD6gdX%2FD1PQZdMrR5euP8C3eYDfV%2B%2FRRjWVpuA3ETduebMgxjXsqU896hpNcwm7OcsVIqrxCw4OGC0Q9gn8eywogLmNnmaZGleLyv048q4ZSJr%2FHV9GuT5TxivcDg2GVV%2BZWgJ7gG7Jc3xOS4T5fDb9ey3OSyySxK4hGK4oXvHsl7VlNogBdoCeULNDCO6iOWVq10WkhjCsgozJSzb1LOu3zUHSzPV28aLQTUHaEnqdG67u%2Faf0IyN337tD5qQ4uJdDkNunpgHVhsspAM5%2BSx849%2BJR7XprkXuEs%2BkUmXzTHG9ST%2BugywMDZo0C41q%2FWK2w4RUcI%2F%2Bt7vZQiHyIUGLQILD5eIqf8HEwz63LZOVgDFiSRG7cGc1goTGX%2FFb%2FYf2hAtsflPYOKMBiYy1CwNJ57rVKo8JqNTmTUufhCD05Dqf7RPE5q4nerFvi1SLg4TrXFUtw37HwggIzJJKaLIgww%2BuL1wY6sgFC%2F8kuSwxNekGBFnPrHu%2FTGf%2BD%2FBz6u6pRTe%2Fb67YKxcLm2Dymt%2Fiy2VmZ6RdX8V98hPLeA1sWQjb6ppd20Q4JoYF3%2FWQ0bsouk7SXjkRs8Fk21WDePnYv2oBC8P3mCo9tDuLyUv8MbxuamlcenIb9nmRojb%2Bh8hZ58oKR4XxjQTcYcjClN7WICACxZCEEgiLvk25iO6CeBDWXfhRlR6inT3QdNV4tYFMesY0Rb1YymoRr&amp;X-Amz-Algorithm=AWS4-HMAC-SHA256&amp;X-Amz-Credential=ASIAT7MQN47UX2GMWDFB%2F20261029%2Feu-west-1%2Fs3%2Faws4_request&amp;X-Amz-Date=20261029T080859Z&amp;X-Amz-SignedHeaders=host&amp;X-Amz-Expires=900&amp;X-Amz-Signature=ea51aefd75cfa2fba3d7627aaefd228e30883d948fdce9e31b00abc536cc0980 266w\" sizes=\"(max-width: 353px) 100vw, 353px\" \/><\/a><\/p>\n<p>(a) Calculate the total resistance of the circuit.<br \/>\n(b) The current through the 4 \uf057 resistor is 3 A. Calculate the voltage across R3.<br \/>\n(c) State the voltage across R1 and R2.<br \/>\n(d) State the reading on meter V1.<br \/>\n(e) Calculate the current through:<br \/>\n(i) Resistor R1;<br \/>\n(ii) Resistor R2.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>1. A circuit consists of two resistors connected in series. (a) Calculate the total resistance of the circuit. (b) A 9 V cell is used as the power source. Calculate the current in the circuit (c) Calculate the readings on: (i) Voltmeter V1; (ii) Voltmeter V2. 2. A pupil connects three resistors as shown in &hellip; <a href=\"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/ppp-exercise-4b\/\" class=\"more-link\">Continue reading <span class=\"screen-reader-text\">PPP Exercise 4B<\/span> <span class=\"meta-nav\">&rarr;<\/span><\/a><\/p>\n","protected":false},"author":2454,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"open","ping_status":"open","template":"","meta":{"footnotes":""},"class_list":["post-126","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/wp-json\/wp\/v2\/pages\/126","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/wp-json\/wp\/v2\/users\/2454"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/wp-json\/wp\/v2\/comments?post=126"}],"version-history":[{"count":3,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/wp-json\/wp\/v2\/pages\/126\/revisions"}],"predecessor-version":[{"id":153,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/wp-json\/wp\/v2\/pages\/126\/revisions\/153"}],"wp:attachment":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsecphyprelimpractice\/wp-json\/wp\/v2\/media?parent=126"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}