{"id":12,"date":"2014-10-21T09:35:01","date_gmt":"2014-10-21T09:35:01","guid":{"rendered":"http:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu3hwrk\/?page_id=12"},"modified":"2014-10-21T09:45:29","modified_gmt":"2014-10-21T09:45:29","slug":"equilibrium","status":"publish","type":"page","link":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu3hwrk\/equilibrium\/","title":{"rendered":"Equilibrium"},"content":{"rendered":"<p><strong>1.<\/strong>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 The reaction between SO<sub>2<\/sub> and O<sub>2<\/sub> may be described as<\/p>\n<p>2SO<sub>2(g)<\/sub> + O<sub>2(g)<\/sub> \u00a02SO<sub>3(g)<\/sub><strong><em>\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/em><\/strong>\u0394H = -196 kJ mol<sup>-1<\/sup><\/p>\n<p>Select the two conditions that will favour a high yield of SO<sub>3.<\/sub><\/p>\n<p>A\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Removal of SO<sub>2<\/sub><\/p>\n<p>B\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Lower the pressure<\/p>\n<p>C\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Lower the temperature<\/p>\n<p>D\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Use a catalyst<\/p>\n<p>E\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Addition of more O<sub>2<\/sub><\/p>\n<p><strong>2.<\/strong>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 A chemical reaction has reached dynamic equilibrium at a certain temperature. Which one of following statements is <strong>incorrect<\/strong>?<\/p>\n<p>A\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 The reaction has stopped completely<\/p>\n<p>B\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 The concentrations of the reactants remains constant<\/p>\n<p>C\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Products are continuously being formed<\/p>\n<p>D\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 The rate of the forward reaction is equal to the rate of the reverse reaction<\/p>\n<p><strong>3.<\/strong>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Three moles of ethanol and three moles of ethanoic acid were reacted together according to the equation<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C<sub>2<\/sub>H<sub>5<\/sub>OH + CH<sub>3<\/sub>COOH\u00a0 \u00a0\u00a0CH<sub>3<\/sub>COOC<sub>2<\/sub>H<sub>5<\/sub> + H<sub>2<\/sub>O<\/p>\n<p>At equilibrium, there was 2 moles each of ethyl ethanoate and water formed. What is the \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 equilibrium constant for this reaction?<\/p>\n<p>A\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 4<\/p>\n<p>B\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 2<\/p>\n<p>C\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 0.25<\/p>\n<p>D\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 0.44<\/p>\n<p><strong>4.<\/strong> In which of the following would a change in pressure not affect the yield of product<\/p>\n<p><strong>\u00a0<\/strong><\/p>\n<p><strong>5.<\/strong> A catalyst is added to a chemical reaction at equilibrium. Which statement about catalysts is correct?<\/p>\n<p><strong>6.<\/strong> Nitrogen dioxide can be produced in a number of ways but industrially it is produced using the Ostwald process. Inthe first stage of this process nitrogen monoxide is produced by passing over a hot catalyst.<\/p>\n<p>In the second stage of this process the nitrogen monoxide combines with oxygen in an exothermic reaction to produce nitrogen dioxide.<\/p>\n<p>What happens to the yield of nitrogen dioxide if the reaction mixture in stage 2 is cooled?<\/p>\n<p><strong>7.<\/strong> One method used to produce methanol requires synthesis gas. The following equation shows the production of methanol from synthesis gas.<\/p>\n<p>Which line in the table shows the conditions that would cause the greatest increase in the amount of methanol produced?<\/p>\n<p><strong>8. <\/strong>If the yield of ammonia at equilibrium is 15% then the equilibrium position lies\u2026<\/p>\n<p><strong>A <\/strong>well to the right<\/p>\n<p><strong>B <\/strong>well to the left<\/p>\n<p><strong>C <\/strong>almost centrally<\/p>\n<p><strong>D <\/strong>equally to each side<\/p>\n<p><strong>9.<\/strong> Equilibrium is reached when the rate of the forward reaction\u2026\u2026\u2026\u2026<\/p>\n<p><strong>\u00a0<\/strong><\/p>\n<p><strong>A <\/strong>reaches zero<\/p>\n<p><strong>B <\/strong>reaches its minimum<\/p>\n<p><strong>C <\/strong>equals the back reaction rate<\/p>\n<p><strong>D <\/strong>is twice the back reactionrate<\/p>\n<p><strong>10. <\/strong>If the equilibrium position for a reaction lies well to the right, then the equilibrium mixture will contain\u2026<\/p>\n<p><strong>\u00a0<\/strong><\/p>\n<p><strong>A <\/strong>more products than reactants<\/p>\n<p><strong>B <\/strong>more reactants than products<\/p>\n<p><strong>C <\/strong>only reactants<\/p>\n<p><strong>D <\/strong>only products<\/p>\n<p><strong>\u00a0<\/strong><\/p>\n<p><strong>11. <\/strong>Starting with NH<sub>3<\/sub> rather than N<sub>2<\/sub> and H<sub>2<\/sub> , would give an equilibrium mixture with..<\/p>\n<p><strong>A <\/strong>a greater proportion of ammonia<\/p>\n<p><strong>B <\/strong>less nitrogen<\/p>\n<p><strong>C <\/strong>the same proportions of all three gases<\/p>\n<p><strong>D <\/strong>less ammonia than before<\/p>\n<p><strong>12.<\/strong> Which conditions would give the best yield of Hydrogen at equilibrium in this reaction?<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 CH<sub>4<\/sub>(g) + H\u00adO(g)\u2194CO(g) + 3H<sub>2<\/sub>(g)\u00a0\u00a0\u00a0 \u0394= +210kJ<\/p>\n<p><strong>A <\/strong>High temperature and low pressure<\/p>\n<p><strong>B <\/strong>High temperature and high pressure<\/p>\n<p><strong>C <\/strong>Low temperature and low pressure<\/p>\n<p><strong>D <\/strong>Low temperature and high pressure<\/p>\n<p><strong>\u00a0<\/strong><\/p>\n<p><strong>13. <\/strong>In which reaction below will a change in pressure have no effect on the composition of the equilibrium mixture?<\/p>\n<p><strong>A <\/strong>4NH<sub>3<\/sub>(g) + 5O<sub>2<\/sub>(g) \u2194 4NO<sub>2<\/sub>(g) + 6H<sub>2<\/sub>O(l)<\/p>\n<p><strong>B <\/strong>2SO<sub>2<\/sub> (g) + O<sub>2<\/sub>(g) \u2194 2SO<sub>3<\/sub>(g)<\/p>\n<p><strong>C <\/strong>CO(g) + H<sub>2<\/sub>O(g) \u2194 CO<sub>2<\/sub>(g) + H<sub>2<\/sub>O(g)<\/p>\n<p><strong>D <\/strong>C<sub>2<\/sub>H<sub>4<\/sub>(g) + H<sub>2<\/sub>O(g) \u2194 C<sub>2<\/sub>H<sub>5<\/sub>OH(g)<\/p>\n<p><strong>14.<\/strong> Ammonia gas dissolves in water to form an alkaline solution.<\/p>\n<p>NH<sub>3<\/sub>(g) + H<sub>2<\/sub>O(l) \u2194 NH<sub>4<\/sub> <sup>+<\/sup> (aq) + OH<sup>&#8211;<\/sup> (aq) \u0394H = -31kJ<\/p>\n<p>How would each of the following changes affect the position of equilibrium?<\/p>\n<p><strong>a) <\/strong>Increasing the temperature.<\/p>\n<p><strong>b) <\/strong>Increasing the pressure<strong>. <\/strong><\/p>\n<p><strong>c) <\/strong>Adding ammonium chloride.<\/p>\n<p><strong>15.<\/strong>\u00a0\u00a0\u00a0\u00a0\u00a0 The diagram shows the concentrations of hydrogen, iodine and hydrogen iodide for the reaction between hydrogen and iodine.<\/p>\n<p>Which of the following statements is <strong>incorrect<\/strong>?<\/p>\n<p>A \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 the equilibrium lies predominantly to the left<\/p>\n<p>B\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 at point A on the time axis, the concentration of all three gases is zero<\/p>\n<p>C \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 The reaction between the gases reaches equilibrium at point B.<\/p>\n<p>D\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Adding more hydrogen at point D will alter\u00a0\u00a0 the shape of the graph.<\/p>\n<p>E\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 At point C, the system is in a state of dynamic equilibrium.<\/p>\n<p><strong>16.<\/strong>\u00a0\u00a0\u00a0\u00a0\u00a0 Consider the following equilibrium reaction<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<br \/>\nWhich one of the following will cause a yellow colour to predominate?<\/p>\n<p>A\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Addition of sodium hydroxide (NaOH)<\/p>\n<p>B\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Addition of sodium chromate (Na<sub>2<\/sub>CrO<sub>4<\/sub>)<\/p>\n<p>C\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Addition of hydrochloric acid (HCl)<\/p>\n<p>D\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Removal of water<\/p>\n<p><strong>17.<\/strong>\u00a0\u00a0\u00a0\u00a0\u00a0 Which one of the following equilibrium reactions is <strong>not<\/strong> affected by a change in pressure?<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 A\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C\u00a0<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D<\/p>\n<p><strong>18.<\/strong>\u00a0\u00a0\u00a0\u00a0\u00a0 What does it mean to say that a chemical reaction has reached equilibrium?<\/p>\n<p><strong>19.<\/strong>\u00a0\u00a0\u00a0\u00a0\u00a0 The forward reaction of the equilibrium system below is endothermic. Dilute HCl is added and the colour changes to blue.\u00a0 What colour change occurs when the mixture is cooled?<\/p>\n<p><strong>20.<\/strong>\u00a0\u00a0\u00a0\u00a0\u00a0 The reaction of nitrogen dioxide (NO<sub>2<\/sub>) forming dinitrogen tetroxide (N<sub>2<\/sub>O<sub>4<\/sub>) is exothermic in the \u00a0\u00a0\u00a0\u00a0 forward direction.<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/p>\n<p>State <strong>two<\/strong> conditions will cause the equilibrium mixture to go dark brown?<\/p>\n<p><strong>21.<\/strong>\u00a0\u00a0\u00a0\u00a0\u00a0 Ammonia is formed in the Haber process according to the following balanced equation.<\/p>\n<p>N<sub>2 <\/sub>+ 3H<sub>2<\/sub>\u00a0 \u00a02NH<sub>3<\/sub><\/p>\n<p><strong><em>\u00a0<\/em><\/strong><\/p>\n<p>The table shows the percentages of ammonia present at equilibrium under different conditions of temperature T and pressure P when hydrogen and nitrogen gases were mixed in a 3:1 molar ratio. Is this an endothermic or exothermic reaction? Give a reason for your answer.<\/p>\n<p><strong>22.<\/strong>\u00a0\u00a0\u00a0\u00a0\u00a0 The following equilibrium involves two compounds of phosphorus.<\/p>\n<p>PCl<sub>3(g)<\/sub>\u00a0\u00a0\u00a0 +\u00a0\u00a0 3NH<sub>3<\/sub>\u00a0<sub>(g)<\/sub>\u00a0\u00a0 <strong><em>\u00a0<\/em><\/strong>\u00a0\u00a0\u00a0\u00a0P(NH<sub>2<\/sub>)<sub>3(g)<\/sub>\u00a0\u00a0\u00a0 +\u00a0\u00a0 3HCl<sub>(g)<\/sub><\/p>\n<p>(a)\u00a0 An increase in temperature moves the equilibrium to the left. \u00a0What does this indicate about the enthalpy change for the forward reaction?\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0<\/p>\n<p>(b)\u00a0 What effect, if any, will an increase in pressure have on the equilibrium?<\/p>\n<p><strong>23.<\/strong> \u00a0\u00a0\u00a0\u00a0 The balanced equation for a reaction at equilibrium is:<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <strong>aA + bB\u00a0 <\/strong><strong><em><\/em><\/strong><strong>\u00a0\u00a0\u00a0cC\u00a0 +\u00a0 dD<\/strong><\/p>\n<p>(a)\u00a0 For this reaction, the equilibrium constant, K, can be defined as:<\/p>\n<p>where [A] represents the concentration of A, etc and a represents the number of moles of A,etc.<\/p>\n<p>(i)\u00a0 Write down the expression for the equilibrium constant for the following \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0equilibrium.<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 N<sub>2<\/sub>(g)\u00a0 + 3H<sub>2<\/sub>(g) <strong><em><\/em><\/strong>\u00a0\u00a02NH<sub>3<\/sub>(g)\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/p>\n<p>(ii)\u00a0 What will happen to the position of the equilibrium if the reaction is carried out over a catalyst?\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/p>\n<p>(b)\u00a0 In industry, the reaction of nitrogen with hydrogen to produce ammonia by the Haber Process does not attain equilibrium.<\/p>\n<p>Give one feature of the operating conditions which leads to the Haber Process not reaching equilibrium<\/p>\n<p><strong>24.<\/strong>\u00a0\u00a0\u00a0\u00a0\u00a0 When a yellow solution of iron (III) chloride (FeCl<sub>3<\/sub>)and a colourless solution of potassium thiocyanate (KCNS) were mixed in a test tube, a red colour appeared and the following\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 equilibrium was established:<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Fe<sup>3+<\/sup><sub>(aq)<\/sub>\u00a0\u00a0 +\u00a0\u00a0 CNS<sup>&#8211;<\/sup><sub>(aq) <\/sub>\u00a0 \u00a0\u00a0\u00a0\u00a0Fe(CNS)<sup>2+<\/sup><sub>(aq)<\/sub><\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 yellow\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0 red<\/p>\n<p>Explain:<\/p>\n<p>(a) the effect on the Fe<sup>3+<\/sup> ion concentration of adding KCNS to the equilibrium mixture<\/p>\n<p>(b) why changing the pressure has no effect on this reaction.<\/p>\n<p><strong>25.<\/strong>\u00a0\u00a0\u00a0\u00a0\u00a0 Consider the following equilibrium reaction at room temperature used to dissolve iodine (I<sub>2<\/sub>) \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 crystals in an aqueous solution of iodide ions (I<sup>&#8211;<\/sup>).<\/p>\n<p>I<sub>2(aq)<\/sub>\u00a0 +\u00a0\u00a0 I <sup>&#8211;<\/sup><sub>(aq)\u00a0 <\/sub>\u00a0I<sub>3<\/sub><sup>&#8211;<\/sup><sub>(aq)<\/sub><\/p>\n<p>State and explain the effect on the equilibrium concentration of triiodide ions of adding a substance that reacts with iodine, eg. starch.<\/p>\n<p><strong>26.<\/strong> Iodine monochloride and chlorine gas react together to establish the following equilibrium in a closed system.<\/p>\n<p>Which line in the table shows the conditions that would cause the greatest increase in the amount of ICl<sub>3<\/sub> produced in this reaction.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>1.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 The reaction between SO2 and O2 may be described as 2SO2(g) + O2(g) \u00a02SO3(g)\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u0394H = -196 kJ mol-1 Select the two conditions that will favour a high yield of SO3. A\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Removal of SO2 B\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Lower the pressure C\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Lower the temperature D\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Use a catalyst E\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Addition of more O2 2.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 &hellip; <a href=\"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu3hwrk\/equilibrium\/\" class=\"more-link\">Continue reading<span class=\"screen-reader-text\"> &#8220;Equilibrium&#8221;<\/span><\/a><\/p>\n","protected":false},"author":2454,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"open","ping_status":"open","template":"","meta":{"footnotes":""},"class_list":["post-12","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu3hwrk\/wp-json\/wp\/v2\/pages\/12","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu3hwrk\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu3hwrk\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu3hwrk\/wp-json\/wp\/v2\/users\/2454"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu3hwrk\/wp-json\/wp\/v2\/comments?post=12"}],"version-history":[{"count":3,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu3hwrk\/wp-json\/wp\/v2\/pages\/12\/revisions"}],"predecessor-version":[{"id":34,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu3hwrk\/wp-json\/wp\/v2\/pages\/12\/revisions\/34"}],"wp:attachment":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu3hwrk\/wp-json\/wp\/v2\/media?parent=12"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}