Reagent in excess

1.        Iron(II) sulphide reacts with hydrochloric acid as follows:

            FeS(s)   +   2HCl(aq)  à     FeCl2(aq)   +   H2S(g)

If 4.4g of iron(II) sulphide was added to 160cm3 of 0.5 mol l-1 hydrochloric acid, show by calculation which substance is in excess.

2.        A student added 0.20g of silver nitrate, AgNO3, to 25 cm3 of water. This solution was then added to 20cm3 of 0.0010 mol l-1 hydrochloric acid. The equation for the reaction is:

            AgNO3(aq)   +   HCl(aq)     à AgCl(s)   +   HNO3(aq)

Show by calculation which reactant is in excess.

3.        Calcite is a very pure form of calcium carbonate which reacts with nitric acid as follows:

            CaCO3(s)   +   2HNO3(aq)  à Ca(NO3)2(aq)   +   H2O(l)  +  CO2(g)

 A 2.14g piece of calcite was added to 50.0cm3 of 0.200 mol l-1 nitric acid in a beaker.

Calculate the mass of calcite, in grams, left unreacted.

4.        Copper(II) oxide reacts with sulphuric acid as follows:

            CuO(s)   +   H2SO4(aq) à CuSO4(aq)   +   H2O(l)

1.6 g of copper(II) oxide is added to a beaker containing 50cm3 of 0.25 mol l-1 sulphuric acid.

Calculate the mass of copper(II) oxide remaining after the reaction was complete.

5.        Lead reacts with hydrochloric acid as follows:

            Pb(s)   +   2HCl(aq) à PbCl2(aq)   +   H2(g)

If 6.22g of lead was added to 50cm3 of 1 mol l-1 hydrochloric acid, calculate the mass of lead left unreacted.

6.        A strip of zinc metal weighing 2.00 g is placed in an aqueous solution containing 10.00 g of silver nitrate. The reaction that occurs is

            Zn(s) + 2AgNO3(aq) à 2Ag(s) + Zn(NO3)2(aq)

(a) Determine which reactant is in excess.

(b) Calculate how many grams of silver will be formed.

7.        A piece of lithium with a mass of 1.50 g is placed in an aqueous solution containing 6.00 g of copper (II) sulphate.  The reaction that occurs is:

            2Li(s) + CuSO4(aq) à Cu + Li2SO4 (aq)

(a) Determine which reactant is in excess.

(b) Calculate how many grams of copper will be formed.

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