{"id":779,"date":"2015-11-27T08:36:30","date_gmt":"2015-11-27T08:36:30","guid":{"rendered":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/?page_id=779"},"modified":"2015-12-26T12:38:20","modified_gmt":"2015-12-26T12:38:20","slug":"exercise-1_1a-w9c-help-card","status":"publish","type":"page","link":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/exercise-1_1a-w9c-help-card\/","title":{"rendered":"Exercise 1_1C W14(c) Help Card"},"content":{"rendered":"<table>\n<tbody>\n<tr>\n<td><a title=\"Exercise 1_1C Rates Extension\" href=\"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/exercise-1_1c-reaction-rates\/\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-54\" src=\"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemextra\/files\/2015\/09\/Picture4.jpg\" alt=\"Picture4\" width=\"100\" height=\"48\" \/><\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<table>\n<tbody>\n<tr>\n<td><a href=\"https:\/\/blogs.glowscotland.org.uk\/gc\/public\/hyndsechchemu1hwrk\/uploads\/sites\/5080\/2015\/09\/Picture13.jpg\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-624\" src=\"https:\/\/blogs.glowscotland.org.uk\/gc\/public\/hyndsechchemu1hwrk\/uploads\/sites\/5080\/2015\/09\/Picture13.jpg\" alt=\"Picture13\" width=\"600\" height=\"285\" srcset=\"https:\/\/blogs.glowscotland.org.uk\/gc\/public\/hyndsechchemu1hwrk\/uploads\/sites\/5080\/2015\/09\/Picture13.jpg 898w, 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300w\" sizes=\"auto, (max-width: 600px) 85vw, 600px\" \/><\/a><\/td>\n<\/tr>\n<tr>\n<td>At first this might seem a bit daunting.\u00a0 However, it can be assumed that only copper(II) carbonate has reacted in this experiment.\u00a0 As the copper (II) carbonate\u00a0reacts,\u00a0carbon dioxide is released, causing the fall in mass.From the mass of carbon dioxide, we can work out the number of moles of carbon dioxide we have lost.<\/p>\n<p>If we know the molar relationship between the copper(II) carbonate and carbon dioxide &#8211; from the balanced equation, then we can work out the number of moles and hence the mass of copper(II) carbonate which must have originally been present.<\/p>\n<p><a href=\"https:\/\/blogs.glowscotland.org.uk\/gc\/public\/hyndsechchemu1hwrk\/uploads\/sites\/5080\/2015\/11\/Screen-Shot-2015-12-26-at-12.35.13.jpg\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-1184\" 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300w\" sizes=\"auto, (max-width: 600px) 85vw, 600px\" \/><\/a><\/p>\n<p>For help on molar ratios (this is covered in Unit 3) &#8211; click <a href=\"http:\/\/www.bbc.co.uk\/education\/guides\/z8fvvcw\/revision\/2\" target=\"_blank\">this link<\/a>.<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"<p>At first this might seem a bit daunting.\u00a0 However, it can be assumed that only copper(II) carbonate has reacted in this experiment.\u00a0 As the copper (II) carbonate\u00a0reacts,\u00a0carbon dioxide is released, causing the fall in mass.From the mass of carbon dioxide, we can work out the number of moles of carbon dioxide we have lost. If &hellip; <a href=\"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/exercise-1_1a-w9c-help-card\/\" class=\"more-link\">Continue reading<span class=\"screen-reader-text\"> &#8220;Exercise 1_1C W14(c) Help Card&#8221;<\/span><\/a><\/p>\n","protected":false},"author":2454,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":""},"class_list":["post-779","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/wp-json\/wp\/v2\/pages\/779","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/wp-json\/wp\/v2\/users\/2454"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/wp-json\/wp\/v2\/comments?post=779"}],"version-history":[{"count":14,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/wp-json\/wp\/v2\/pages\/779\/revisions"}],"predecessor-version":[{"id":1187,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/wp-json\/wp\/v2\/pages\/779\/revisions\/1187"}],"wp:attachment":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/wp-json\/wp\/v2\/media?parent=779"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}