{"id":1454,"date":"2016-03-11T08:12:16","date_gmt":"2016-03-11T08:12:16","guid":{"rendered":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/?page_id=1454"},"modified":"2016-03-11T08:42:31","modified_gmt":"2016-03-11T08:42:31","slug":"exercise-1_1c-w11-help-card","status":"publish","type":"page","link":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/exercise-1_1c-w11-help-card\/","title":{"rendered":"Exercise 1_1C W11 Help Card"},"content":{"rendered":"

\"LO1_A1\"<\/a><\/p>\n\n\n\n\n\n\n\n
\"Picture13\"<\/a><\/td>\nYou may well have carried out this experiment in class.\u00a0 When the\u00a0calcium carbonate is added to the flask, it fizzes and bubbles.\u00a0 We are measuring the rate of reaction using change in mass, due to loss of gas.<\/p>\n

Why might the bubbles cause our results to be\u00a0wrong, and how would the cotton wool plug help in this regard?<\/td>\n<\/tr>\n

\"Picture14\"<\/a><\/td>\nIn this question, the term average can be confusing. We call it an average rate because the rate is changing as the reaction proceeds in the first 10 seconds of the reaction, as shown by the changes in the values. ( A constant rate would produce a constant change).<\/p>\n

The average rate is simply calculated in these circumstance by examining the change in quantity and dividing that by the time taken.<\/p>\n

\"Picture1\"<\/a><\/td>\n<\/tr>\n

\"Picture15\"<\/a><\/td>\nAt first sight this may appear daunting, but\u00a0take time to\u00a0reread the question, including the stem of the question carefully.<\/p>\n

The information you require to answer this question is held in the stem of the question\u00a0and the graph.\u00a0 You should appreciate that this is simply a more complicated presentation of a calculation based on equation, the type you were able to do at National 5 level.<\/p>\n

The balanced equation is provide in the stem of the question.<\/p>\n

From that you can establish a molar ratio between the copper (II)\u00a0carbonate and carbon dioxide.<\/p>\n

The mass of carbon dioxide produced is obtained from the graph, and so the mass of copper (II) carbonate can be calculated.<\/p>\n

Don’t be put off by the complex way the question is presented.<\/td>\n<\/tr>\n

<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n\"Bitesize<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

 <\/p>\n","protected":false},"excerpt":{"rendered":"

You may well have carried out this experiment in class.\u00a0 When the\u00a0calcium carbonate is added to the flask, it fizzes and bubbles.\u00a0 We are measuring the rate of reaction using change in mass, due to loss of gas. Why might the bubbles cause our results to be\u00a0wrong, and how would the cotton wool plug help … Continue reading “Exercise 1_1C W11 Help Card”<\/span><\/a><\/p>\n","protected":false},"author":2454,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":""},"class_list":["post-1454","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/wp-json\/wp\/v2\/pages\/1454","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/wp-json\/wp\/v2\/users\/2454"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/wp-json\/wp\/v2\/comments?post=1454"}],"version-history":[{"count":3,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/wp-json\/wp\/v2\/pages\/1454\/revisions"}],"predecessor-version":[{"id":1459,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/wp-json\/wp\/v2\/pages\/1454\/revisions\/1459"}],"wp:attachment":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hyndsechchemu1hwrk\/wp-json\/wp\/v2\/media?parent=1454"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}