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This question can be a little tricky.
A number of approaches are possible. Probably it is easiest to recognise that the activation energy of the reverse reaction is 30 kJ mol-1 greater than the forward reaction – this is because the enthalpy of the product (for the forward reaction) is 30 kJ mol-1 lower than that of the reactant. The catalyst reduces the Activation Energy (EA) by the same amount for both the forward and reverse reactions, but will not change the enthalpy change (or enthalpy of the chemicals involved). |
