{"id":287,"date":"2016-01-20T15:05:46","date_gmt":"2016-01-20T15:05:46","guid":{"rendered":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/?page_id=287"},"modified":"2019-03-27T08:55:02","modified_gmt":"2019-03-27T08:55:02","slug":"answers-exercise-2_1a-enthalpy","status":"publish","type":"page","link":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/answers-exercise-2_1a-enthalpy\/","title":{"rendered":"Answers: Exercise 1_2A Enthalpy"},"content":{"rendered":"

 <\/p>\n

 <\/p>\n\n\n\n\n\n\n\n\n\n\n\n\n
1.<\/td>\n\u00a0C<\/td>\n<\/tr>\n
\u00a02.<\/td>\n\u00a0B<\/td>\n<\/tr>\n
\u00a03.<\/td>\n\u00a0D<\/td>\n<\/tr>\n
\u00a04.<\/td>\n\u00a0B<\/td>\n<\/tr>\n
\u00a05.<\/td>\n\u00a0D<\/td>\n<\/tr>\n
\u00a06.<\/td>\n\u00a0D<\/td>\n<\/tr>\n
\u00a07.<\/td>\n\u00a0D<\/td>\n<\/tr>\n
\u00a08.<\/td>\n\u00a0A<\/td>\n<\/tr>\n
\u00a09.<\/td>\n\u00a0B<\/td>\n<\/tr>\n
\u00a010.<\/td>\n\u00a0B<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

 <\/p>\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
11.<\/td>\n<\/td>\n<\/tr>\n
a)<\/td>\n
\n<\/a>\"Picture5\"<\/a><\/td>\n<\/tr>\n
<\/td>\n\u00a0Line showing position of EA.<\/td>\n<\/tr>\n
<\/td>\n<\/td>\n<\/tr>\n
12.<\/td>\nB<\/td>\n<\/tr>\n
\u00a013.<\/td>\n\u00a0\u00a0a)\"Picture1\"<\/a><\/td>\n<\/tr>\n
i)<\/td>\nActivation energy = \u00a070kj mol-1<\/sup>
\nEnthalpy change\u00a0 = +40 kj mol-1<\/sup><\/td>\n<\/tr>\n
ii)<\/td>\n\u00a0Activation energy =\u00a0\u00a030kj mol-1<\/sup>
\nEnthalpy change\u00a0 = -40 kj mol-1<\/sup><\/td>\n<\/tr>\n
\u00a0\u00a0b)<\/td>\n\u00a0Activation energy would be reduced by use of a catalyst.<\/td>\n<\/tr>\n
\u00a014.<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n\u00a0\"Picture8\"<\/a><\/td>\n<\/tr>\n
<\/td>\n\u00a0\"Picture6\"<\/a><\/td>\n<\/tr>\n
\u00a015.<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n\u00a0\"Picture6\"<\/a><\/td>\n<\/tr>\n
<\/td>\n\u00a0\"Picture7\"<\/a><\/td>\n<\/tr>\n
<\/td>\n
\n<\/a>\"Picture1\"<\/a><\/td>\n<\/tr>\n
<\/td>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"

    1. \u00a0C \u00a02. \u00a0B \u00a03. \u00a0D \u00a04. \u00a0B \u00a05. \u00a0D \u00a06. \u00a0D \u00a07. \u00a0D \u00a08. \u00a0A \u00a09. \u00a0B \u00a010. \u00a0B   11. a) \u00a0Line showing position of EA. 12. B \u00a013. \u00a0\u00a0a) i) Activation energy = \u00a070kj mol-1 Enthalpy change\u00a0 = +40 kj mol-1 ii) \u00a0Activation energy =\u00a0\u00a030kj mol-1 Enthalpy change\u00a0 = -40 … Continue reading “Answers: Exercise 1_2A Enthalpy”<\/span><\/a><\/p>\n","protected":false},"author":2454,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"open","ping_status":"closed","template":"","meta":{"footnotes":""},"class_list":["post-287","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/pages\/287","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/users\/2454"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/comments?post=287"}],"version-history":[{"count":17,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/pages\/287\/revisions"}],"predecessor-version":[{"id":1432,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/pages\/287\/revisions\/1432"}],"wp:attachment":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/media?parent=287"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}