{"id":1732,"date":"2020-01-10T10:18:01","date_gmt":"2020-01-10T10:18:01","guid":{"rendered":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/?page_id=1732"},"modified":"2020-01-12T07:11:08","modified_gmt":"2020-01-12T07:11:08","slug":"answers-mcq-online-exercise-3_6a-hesss-law","status":"publish","type":"page","link":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/answers-mcq-online-exercise-3_6a-hesss-law\/","title":{"rendered":"Answers: MCQ Online Exercise 3_6A Hess’s Law"},"content":{"rendered":"

 <\/p>\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
1.<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n\u00a0-672 kJ mol-1<\/sup><\/td>\n<\/tr>\n
<\/td>\n\u00a0\"\"<\/a><\/td>\n<\/tr>\n
\u00a02.<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n\u00a0+206 kj mol-1<\/sup><\/td>\n<\/tr>\n
<\/td>\n\u00a0\"\"<\/a><\/td>\n<\/tr>\n
<\/td>\n\u00a0\"\"<\/a><\/td>\n<\/tr>\n
\u00a03.<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n\u00a0-2168 kj mol-1<\/sup><\/td>\n<\/tr>\n
<\/td>\n\u00a0\"\"<\/a><\/td>\n<\/tr>\n
\u00a0 4.<\/td>\n<\/td>\n<\/tr>\n
\u00a0a)<\/td>\n\u00a0
\n<\/a><\/td>\n<\/tr>\n
<\/td>\n\u00a0\"\"<\/a><\/td>\n<\/tr>\n
\u00a0b)<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n\n
\u00a0Reagent A - H2<\/sub>\r\n\r\nReagent B - Cl2<\/sub>\r\n\r\nReagent C - HCl<\/pre>\n<\/td>\n<\/tr>\n
<\/td>\n<\/td>\n<\/tr>\n
\u00a05.<\/td>\n<\/td>\n<\/tr>\n
<\/td>\nmolar ratio 1 mole HCl reacts with 1 mole AgNO3<\/sub><\/p>\n

AgNO3<\/sub>: \u00a0n= cv<\/p>\n

0.5 x 0.02 = 0.01 moles.<\/p>\n

[0.01 moles AgNO3<\/sub> can react with 0.01 moles HCl]<\/p>\n

HCl: \u00a0n= cv<\/p>\n

1 X 0.015 = 0.015 moles<\/td>\n<\/tr>\n

<\/td>\n\u00a0Conclusion: \u00a0more moles HCl than AgNO3<\/sub> so HCl is in excess.\u00a0
\n<\/a><\/td>\n<\/tr>\n
<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"

  1. \u00a0-672 kJ mol-1 \u00a0 \u00a02. \u00a0+206 kj mol-1 \u00a0 \u00a0 \u00a03. \u00a0-2168 kj mol-1 \u00a0 \u00a0 4. \u00a0a) \u00a0 \u00a0 \u00a0b) \u00a0Reagent A – H2 Reagent B – Cl2 Reagent C – HCl \u00a05. molar ratio 1 mole HCl reacts with 1 mole AgNO3 AgNO3: \u00a0n= cv 0.5 x 0.02 = 0.01 moles. … Continue reading “Answers: MCQ Online Exercise 3_6A Hess’s Law”<\/span><\/a><\/p>\n","protected":false},"author":2454,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":""},"class_list":["post-1732","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/pages\/1732","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/users\/2454"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/comments?post=1732"}],"version-history":[{"count":6,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/pages\/1732\/revisions"}],"predecessor-version":[{"id":1748,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/pages\/1732\/revisions\/1748"}],"wp:attachment":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/media?parent=1732"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}