{"id":1173,"date":"2019-02-19T09:48:07","date_gmt":"2019-02-19T09:48:07","guid":{"rendered":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/?page_id=1173"},"modified":"2024-06-17T09:50:57","modified_gmt":"2024-06-17T09:50:57","slug":"marking-guide-unit-1b1-reaction-pathways-kinetic-energy-distribution","status":"publish","type":"page","link":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/marking-guide-unit-1b1-reaction-pathways-kinetic-energy-distribution\/","title":{"rendered":"MARKING GUIDE: Unit 1B1 \u2013 Reaction Pathways & Kinetic Energy Distribution"},"content":{"rendered":"\n\n\n\n\n\n\n\n\n\n\n\n
1.<\/td>\n\u00a0A<\/td>\n<\/tr>\n
2.<\/td>\n\u00a0C<\/td>\n<\/tr>\n
3.<\/td>\n\u00a0D<\/td>\n<\/tr>\n
4.<\/td>\n\u00a0B<\/td>\n<\/tr>\n
5.<\/td>\n\u00a0C<\/td>\n<\/tr>\n
6.<\/td>\n\u00a0D<\/td>\n<\/tr>\n
7.<\/td>\n\u00a0A<\/td>\n<\/tr>\n
8.<\/td>\n\u00a0C<\/td>\n<\/tr>\n
9.<\/td>\n\u00a0C<\/td>\n<\/tr>\n
10.<\/td>\nB<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

 <\/p>\n

 <\/p>\n

 <\/p>\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
11.<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n\u00a0D<\/td>\n<\/tr>\n
12.<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n\"\" \"\"<\/td>\n<\/tr>\n
\u00a013.<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n\"\"\"\"<\/td>\n<\/tr>\n
\u00a014.<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n\"\"<\/td>\n<\/tr>\n
\u00a015.<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n\"\"<\/td>\n<\/tr>\n
\u00a016.<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n\u00a0B<\/td>\n<\/tr>\n
\u00a017.<\/td>\n<\/td>\n<\/tr>\n
<\/td>\nA<\/td>\n<\/tr>\n
\u00a018.<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n\u00a0\u00a0a)\"Picture1\"<\/a><\/td>\n<\/tr>\n
i)<\/td>\nActivation energy = \u00a070kJ mol-1<\/sup>
\nEnthalpy change\u00a0 = +40 kJ mol-1<\/sup><\/td>\n<\/tr>\n
ii)<\/td>\n\u00a0Activation energy =\u00a0\u00a030kJ mol-1<\/sup>
\nEnthalpy change\u00a0 = -40 kJ mol-1<\/sup><\/td>\n<\/tr>\n
\u00a0\u00a0b)<\/td>\n\u00a0Activation energy would be reduced by use of a catalyst.<\/td>\n<\/tr>\n
\u00a019.<\/td>\n<\/td>\n<\/tr>\n
\u00a0a)<\/td>\n\u00a0H+<\/sup> ion appears on both reactant and product side – i.e. not used up.<\/td>\n<\/tr>\n
\u00a0b)<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n\"Picture4\"<\/a><\/td>\n<\/tr>\n
20.<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n\u00a0B<\/td>\n<\/tr>\n
21.<\/td>\n<\/td>\n<\/tr>\n
<\/td>\nD<\/td>\n<\/tr>\n
22.<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n\u00a0B<\/td>\n<\/tr>\n
23.<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n\u00a0A<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"

1. \u00a0A 2. \u00a0C 3. \u00a0D 4. \u00a0B 5. \u00a0C 6. \u00a0D 7. \u00a0A 8. \u00a0C 9. \u00a0C 10. B       11. \u00a0D 12. \u00a013. \u00a014. \u00a015. \u00a016. \u00a0B \u00a017. A \u00a018. \u00a0\u00a0a) i) Activation energy = \u00a070kJ mol-1 Enthalpy change\u00a0 = +40 kJ mol-1 ii) \u00a0Activation energy =\u00a0\u00a030kJ mol-1 Enthalpy change\u00a0 = … Continue reading “MARKING GUIDE: Unit 1B1 \u2013 Reaction Pathways & Kinetic Energy Distribution”<\/span><\/a><\/p>\n","protected":false},"author":2454,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":""},"class_list":["post-1173","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/pages\/1173","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/users\/2454"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/comments?post=1173"}],"version-history":[{"count":17,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/pages\/1173\/revisions"}],"predecessor-version":[{"id":2025,"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/pages\/1173\/revisions\/2025"}],"wp:attachment":[{"href":"https:\/\/blogs.glowscotland.org.uk\/gc\/hchemanswers\/wp-json\/wp\/v2\/media?parent=1173"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}